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5(x+1)=5(2x-3)
We move all terms to the left:
5(x+1)-(5(2x-3))=0
We multiply parentheses
5x-(5(2x-3))+5=0
We calculate terms in parentheses: -(5(2x-3)), so:We get rid of parentheses
5(2x-3)
We multiply parentheses
10x-15
Back to the equation:
-(10x-15)
5x-10x+15+5=0
We add all the numbers together, and all the variables
-5x+20=0
We move all terms containing x to the left, all other terms to the right
-5x=-20
x=-20/-5
x=+4
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