7/6(3y-1)-8(1/3)=3/2(2y-5)

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Solution for 7/6(3y-1)-8(1/3)=3/2(2y-5) equation: 



7/6(3y-1)-8(1/3)=3/2(2y-5)

We move all terms to the left:

7/6(3y-1)-8(1/3)-(3/2(2y-5))=0



Domain of the equation: 6(3y-1)!=0

y∈R





Domain of the equation: 2(2y-5))!=0

y∈R



We add all the numbers together, and all the variables

7/6(3y-1)-(3/2(2y-5))-8(+1/3)=0

We multiply parentheses

7/6(3y-1)-(3/2(2y-5))-1/3*8=0

We calculate fractions


(-12y^23/(6(3y-1)*2(2y-5))*3*8)+(336y2/(6(3y-1)*2(2y-5))*3*8)+(-(3*6(3y-1)*3*8)/(6(3y-1)*2(2y-5))*3*8)=0



We calculate terms in parentheses: +(-12y^23/(6(3y-1)*2(2y-5))*3*8), so:

-12y^23/(6(3y-1)*2(2y-5))*3*8

We do not support eypression: y^23

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