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5(x+1)=3(2x+3)+5=
We move all terms to the left:
5(x+1)-(3(2x+3)+5)=0
We multiply parentheses
5x-(3(2x+3)+5)+5=0
We calculate terms in parentheses: -(3(2x+3)+5), so:We get rid of parentheses
3(2x+3)+5
We multiply parentheses
6x+9+5
We add all the numbers together, and all the variables
6x+14
Back to the equation:
-(6x+14)
5x-6x-14+5=0
We add all the numbers together, and all the variables
-1x-9=0
We move all terms containing x to the left, all other terms to the right
-x=9
x=9/-1
x=-9
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