(x+2/2)=9-(x+6)/3

Solution for (x+2/2)=9-(x+6)/3 equation:

(x+2/2)=9-(x+6)/3

We move all terms to the left:

(x+2/2)-(9-(x+6)/3)=0

We add all the numbers together, and all the variables

(x+1)-(9-(x+6)/3)=0

We get rid of parentheses

x-(9-(x+6)/3)+1=0

We multiply all the terms by the denominator


x*3)-(9-(x+6)+1*3)=0

We add all the numbers together, and all the variables

x*3)-(9-(x+6)=0

Wy multiply elements

3x^2-(x+6)=0

We get rid of parentheses

3x^2-x-6=0

We add all the numbers together, and all the variables

3x^2-1x-6=0

a = 3; b = -1; c = -6;
Δ = b2-4ac
Δ = -12-4·3·(-6)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{73}}{2*3}=\frac{1-\sqrt{73}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{73}}{2*3}=\frac{1+\sqrt{73}}{6}
$