5(x+1)+12=-8(x-2)+40

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Solution for 5(x+1)+12=-8(x-2)+40 equation: 



5(x+1)+12=-8(x-2)+40

We move all terms to the left:

5(x+1)+12-(-8(x-2)+40)=0

We multiply parentheses

5x-(-8(x-2)+40)+5+12=0



We calculate terms in parentheses: -(-8(x-2)+40), so:

-8(x-2)+40

We multiply parentheses

-8x+16+40

We add all the numbers together, and all the variables

-8x+56

Back to the equation:

-(-8x+56)



We add all the numbers together, and all the variables

5x-(-8x+56)+17=0

We get rid of parentheses

5x+8x-56+17=0

We add all the numbers together, and all the variables

13x-39=0

We move all terms containing x to the left, all other terms to the right

13x=39

x=39/13

x=3

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