5(w+2)-11=26+(9-7w)

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Solution for 5(w+2)-11=26+(9-7w) equation: 



5(w+2)-11=26+(9-7w)

We move all terms to the left:

5(w+2)-11-(26+(9-7w))=0

We add all the numbers together, and all the variables

5(w+2)-(26+(-7w+9))-11=0

We multiply parentheses

5w-(26+(-7w+9))+10-11=0



We calculate terms in parentheses: -(26+(-7w+9)), so:

26+(-7w+9)

determiningTheFunctionDomain
(-7w+9)+26

We get rid of parentheses

-7w+9+26

We add all the numbers together, and all the variables

-7w+35

Back to the equation:

-(-7w+35)



We add all the numbers together, and all the variables

5w-(-7w+35)-1=0

We get rid of parentheses

5w+7w-35-1=0

We add all the numbers together, and all the variables

12w-36=0

We move all terms containing w to the left, all other terms to the right

12w=36

w=36/12

w=3

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