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2(x-5)=4(2x+5)
We move all terms to the left:
2(x-5)-(4(2x+5))=0
We multiply parentheses
2x-(4(2x+5))-10=0
We calculate terms in parentheses: -(4(2x+5)), so:We get rid of parentheses
4(2x+5)
We multiply parentheses
8x+20
Back to the equation:
-(8x+20)
2x-8x-20-10=0
We add all the numbers together, and all the variables
-6x-30=0
We move all terms containing x to the left, all other terms to the right
-6x=30
x=30/-6
x=-5
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