5(v-4)=2(-4v+3)

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Solution for 5(v-4)=2(-4v+3) equation: 



5(v-4)=2(-4v+3)

We move all terms to the left:

5(v-4)-(2(-4v+3))=0

We multiply parentheses

5v-(2(-4v+3))-20=0



We calculate terms in parentheses: -(2(-4v+3)), so:

2(-4v+3)

We multiply parentheses

-8v+6

Back to the equation:

-(-8v+6)



We get rid of parentheses

5v+8v-6-20=0

We add all the numbers together, and all the variables

13v-26=0

We move all terms containing v to the left, all other terms to the right

13v=26

v=26/13

v=2

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