5(v-4)-2=-6(-3v+1)-v

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Solution for 5(v-4)-2=-6(-3v+1)-v equation: 



5(v-4)-2=-6(-3v+1)-v

We move all terms to the left:

5(v-4)-2-(-6(-3v+1)-v)=0

We multiply parentheses

5v-(-6(-3v+1)-v)-20-2=0



We calculate terms in parentheses: -(-6(-3v+1)-v), so:

-6(-3v+1)-v

We add all the numbers together, and all the variables

-1v-6(-3v+1)

We multiply parentheses

-1v+18v-6

We add all the numbers together, and all the variables

17v-6

Back to the equation:

-(17v-6)



We add all the numbers together, and all the variables

5v-(17v-6)-22=0

We get rid of parentheses

5v-17v+6-22=0

We add all the numbers together, and all the variables

-12v-16=0

We move all terms containing v to the left, all other terms to the right

-12v=16

v=16/-12

v=-1+1/3

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