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5(v-2)=2v+3-5(-3-1)
We move all terms to the left:
5(v-2)-(2v+3-5(-3-1))=0
We add all the numbers together, and all the variables
5(v-2)-(2v+3-5(-4))=0
We multiply parentheses
5v-(2v+3-5(-4))-10=0
We calculate terms in parentheses: -(2v+3-5(-4)), so:We get rid of parentheses
2v+3-5(-4)
We add all the numbers together, and all the variables
2v+23
Back to the equation:
-(2v+23)
5v-2v-23-10=0
We add all the numbers together, and all the variables
3v-33=0
We move all terms containing v to the left, all other terms to the right
3v=33
v=33/3
v=11
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