3x+2=3(4-x)+2(1-6x)

Solution for 3x+2=3(4-x)+2(1-6x) equation:

3x+2=3(4-x)+2(1-6x)

We move all terms to the left:

3x+2-(3(4-x)+2(1-6x))=0

We add all the numbers together, and all the variables

3x-(3(-1x+4)+2(-6x+1))+2=0


We calculate terms in parentheses: -(3(-1x+4)+2(-6x+1)), so:

3(-1x+4)+2(-6x+1)

We multiply parentheses

-3x-12x+12+2

We add all the numbers together, and all the variables

-15x+14

Back to the equation:

-(-15x+14)


We get rid of parentheses

3x+15x-14+2=0

We add all the numbers together, and all the variables

18x-12=0

We move all terms containing x to the left, all other terms to the right

18x=12

x=12/18

x=2/3