5(v-2)-v=3(v+1)

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Solution for 5(v-2)-v=3(v+1) equation: 



5(v-2)-v=3(v+1)

We move all terms to the left:

5(v-2)-v-(3(v+1))=0

We add all the numbers together, and all the variables

-1v+5(v-2)-(3(v+1))=0

We multiply parentheses

-1v+5v-(3(v+1))-10=0



We calculate terms in parentheses: -(3(v+1)), so:

3(v+1)

We multiply parentheses

3v+3

Back to the equation:

-(3v+3)



We add all the numbers together, and all the variables

4v-(3v+3)-10=0

We get rid of parentheses

4v-3v-3-10=0

We add all the numbers together, and all the variables

v-13=0

We move all terms containing v to the left, all other terms to the right

v=13

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