5(b-4)=7(2b+1)

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Solution for 5(b-4)=7(2b+1) equation: 



5(b-4)=7(2b+1)

We move all terms to the left:

5(b-4)-(7(2b+1))=0

We multiply parentheses

5b-(7(2b+1))-20=0



We calculate terms in parentheses: -(7(2b+1)), so:

7(2b+1)

We multiply parentheses

14b+7

Back to the equation:

-(14b+7)



We get rid of parentheses

5b-14b-7-20=0

We add all the numbers together, and all the variables

-9b-27=0

We move all terms containing b to the left, all other terms to the right

-9b=27

b=27/-9

b=-3

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