5(v+1)+v=3(v-2)+2

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Solution for 5(v+1)+v=3(v-2)+2 equation: 



5(v+1)+v=3(v-2)+2

We move all terms to the left:

5(v+1)+v-(3(v-2)+2)=0

We add all the numbers together, and all the variables

v+5(v+1)-(3(v-2)+2)=0

We multiply parentheses

v+5v-(3(v-2)+2)+5=0



We calculate terms in parentheses: -(3(v-2)+2), so:

3(v-2)+2

We multiply parentheses

3v-6+2

We add all the numbers together, and all the variables

3v-4

Back to the equation:

-(3v-4)



We add all the numbers together, and all the variables

6v-(3v-4)+5=0

We get rid of parentheses

6v-3v+4+5=0

We add all the numbers together, and all the variables

3v+9=0

We move all terms containing v to the left, all other terms to the right

3v=-9

v=-9/3

v=-3

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