-22=4(2x+2)2x

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Solution for -22=4(2x+2)2x equation: 



-22=4(2x+2)2x

We move all terms to the left:

-22-(4(2x+2)2x)=0



We calculate terms in parentheses: -(4(2x+2)2x), so:

4(2x+2)2x

We multiply parentheses

16x^2+16x

Back to the equation:

-(16x^2+16x)



We get rid of parentheses

-16x^2-16x-22=0

a = -16; b = -16; c = -22;
Δ = b2-4ac
Δ = -162-4·(-16)·(-22)
Δ = -1152
Delta is less than zero, so there is no solution for the equation

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