5(u-1)-8=-2(-8u+5)-2u

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Solution for 5(u-1)-8=-2(-8u+5)-2u equation: 



5(u-1)-8=-2(-8u+5)-2u

We move all terms to the left:

5(u-1)-8-(-2(-8u+5)-2u)=0

We multiply parentheses

5u-(-2(-8u+5)-2u)-5-8=0



We calculate terms in parentheses: -(-2(-8u+5)-2u), so:

-2(-8u+5)-2u

We add all the numbers together, and all the variables

-2u-2(-8u+5)

We multiply parentheses

-2u+16u-10

We add all the numbers together, and all the variables

14u-10

Back to the equation:

-(14u-10)



We add all the numbers together, and all the variables

5u-(14u-10)-13=0

We get rid of parentheses

5u-14u+10-13=0

We add all the numbers together, and all the variables

-9u-3=0

We move all terms containing u to the left, all other terms to the right

-9u=3

u=3/-9

u=-1/3

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