5(t-5)+2(t-2)=-22

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Solution for 5(t-5)+2(t-2)=-22 equation: 



5(t-5)+2(t-2)=-22

We move all terms to the left:

5(t-5)+2(t-2)-(-22)=0

We add all the numbers together, and all the variables

5(t-5)+2(t-2)+22=0

We multiply parentheses

5t+2t-25-4+22=0

We add all the numbers together, and all the variables

7t-7=0

We move all terms containing t to the left, all other terms to the right

7t=7

t=7/7

t=1

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