(2r+6)/(4)=(3r-12)/(3)

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Solution for (2r+6)/(4)=(3r-12)/(3) equation: 



(2r+6)/(4)=(3r-12)/(3)

We move all terms to the left:

(2r+6)/(4)-((3r-12)/(3))=0

We calculate fractions


2r/()+(-((3r-12)*4)/()=0



We calculate terms in parentheses: +(-((3r-12)*4)/(), so:

-((3r-12)*4)/(

We multiply all the terms by the denominator


-((3r-12)*4)



We calculate terms in parentheses: -((3r-12)*4), so:

(3r-12)*4

We multiply parentheses

12r-48

Back to the equation:

-(12r-48)



We get rid of parentheses

-12r+48

Back to the equation:

+(-12r+48)



We get rid of parentheses

2r/()-12r+48=0

We multiply all the terms by the denominator


2r-12r*()+48*()=0

We add all the numbers together, and all the variables

2r-12r*()=0

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