5(t-2)+3t=4(2t+4)-12

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Solution for 5(t-2)+3t=4(2t+4)-12 equation: 



5(t-2)+3t=4(2t+4)-12

We move all terms to the left:

5(t-2)+3t-(4(2t+4)-12)=0

We add all the numbers together, and all the variables

3t+5(t-2)-(4(2t+4)-12)=0

We multiply parentheses

3t+5t-(4(2t+4)-12)-10=0



We calculate terms in parentheses: -(4(2t+4)-12), so:

4(2t+4)-12

We multiply parentheses

8t+16-12

We add all the numbers together, and all the variables

8t+4

Back to the equation:

-(8t+4)



We add all the numbers together, and all the variables

8t-(8t+4)-10=0

We get rid of parentheses

8t-8t-4-10=0

We add all the numbers together, and all the variables

-14!=0

There is no solution for this equation

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