(-3/4)m=(-24)

Solution for (-3/4)m=(-24) equation:

(-3/4)m=(-24)

We move all terms to the left:

(-3/4)m-((-24))=0


Domain of the equation: 4)m!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

(-3/4)m+24=0

We multiply parentheses

-3m^2+24=0

a = -3; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-3)·24
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{2}}{2*-3}=\frac{0-12\sqrt{2}}{-6}
=-\frac{12\sqrt{2}}{-6}
=-\frac{2\sqrt{2}}{-1}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{2}}{2*-3}=\frac{0+12\sqrt{2}}{-6}
=\frac{12\sqrt{2}}{-6}
=\frac{2\sqrt{2}}{-1}
$