5(t-1)=2(t-4)-6

Solution for 5(t-1)=2(t-4)-6 equation:

5(t-1)=2(t-4)-6

We move all terms to the left:

5(t-1)-(2(t-4)-6)=0

We multiply parentheses

5t-(2(t-4)-6)-5=0


We calculate terms in parentheses: -(2(t-4)-6), so:

2(t-4)-6

We multiply parentheses

2t-8-6

We add all the numbers together, and all the variables

2t-14

Back to the equation:

-(2t-14)


We get rid of parentheses

5t-2t+14-5=0

We add all the numbers together, and all the variables

3t+9=0

We move all terms containing t to the left, all other terms to the right

3t=-9

t=-9/3

t=-3