0.2(2y-1)-2=0.5(3y-5)+3

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Solution for 0.2(2y-1)-2=0.5(3y-5)+3 equation: 



0.2(2y-1)-2=0.5(3y-5)+3

We move all terms to the left:

0.2(2y-1)-2-(0.5(3y-5)+3)=0

We multiply parentheses

0.4y-(0.5(3y-5)+3)-0.2-2=0



We calculate terms in parentheses: -(0.5(3y-5)+3), so:

0.5(3y-5)+3

We multiply parentheses

1.5y-2.5+3

We add all the numbers together, and all the variables

1.5y+0.5

Back to the equation:

-(1.5y+0.5)



We add all the numbers together, and all the variables

0.4y-(1.5y+0.5)-2.2=0

We get rid of parentheses

0.4y-1.5y-0.5-2.2=0

We add all the numbers together, and all the variables

-1.1y-2.7=0

We move all terms containing y to the left, all other terms to the right

-1.1y=2.7

y=2.7/-1.1

y=-2+0.5/1.1

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