5(r-4)-6(2+5r)=-32

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Solution for 5(r-4)-6(2+5r)=-32 equation: 



5(r-4)-6(2+5r)=-32

We move all terms to the left:

5(r-4)-6(2+5r)-(-32)=0

We add all the numbers together, and all the variables

5(r-4)-6(5r+2)-(-32)=0

We add all the numbers together, and all the variables

5(r-4)-6(5r+2)+32=0

We multiply parentheses

5r-30r-20-12+32=0

We add all the numbers together, and all the variables

-25r=0

r=0/-25

r=0

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