7(y+3)=35

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Solution for 7(y+3)=35 equation: 



7(y+3)=35

We move all terms to the left:

7(y+3)-(35)=0

We multiply parentheses

7y+21-35=0

We add all the numbers together, and all the variables

7y-14=0

We move all terms containing y to the left, all other terms to the right

7y=14

y=14/7

y=2

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