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5(r-1)+6=3(4+r)+(2r-1)
We move all terms to the left:
5(r-1)+6-(3(4+r)+(2r-1))=0
We add all the numbers together, and all the variables
5(r-1)-(3(r+4)+(2r-1))+6=0
We multiply parentheses
5r-(3(r+4)+(2r-1))-5+6=0
We calculate terms in parentheses: -(3(r+4)+(2r-1)), so:We add all the numbers together, and all the variables
3(r+4)+(2r-1)
We multiply parentheses
3r+(2r-1)+12
We get rid of parentheses
3r+2r-1+12
We add all the numbers together, and all the variables
5r+11
Back to the equation:
-(5r+11)
5r-(5r+11)+1=0
We get rid of parentheses
5r-5r-11+1=0
We add all the numbers together, and all the variables
-10!=0
There is no solution for this equation
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