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X2+13X-168=0
We add all the numbers together, and all the variables
X^2+13X-168=0
a = 1; b = 13; c = -168;
Δ = b2-4ac
Δ = 132-4·1·(-168)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-29}{2*1}=\frac{-42}{2} =-21 $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+29}{2*1}=\frac{16}{2} =8 $
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