5(r+7)=32+6r

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Solution for 5(r+7)=32+6r equation: 



5(r+7)=32+6r

We move all terms to the left:

5(r+7)-(32+6r)=0

We add all the numbers together, and all the variables

5(r+7)-(6r+32)=0

We multiply parentheses

5r-(6r+32)+35=0

We get rid of parentheses

5r-6r-32+35=0

We add all the numbers together, and all the variables

-1r+3=0

We move all terms containing r to the left, all other terms to the right

-r=-3

r=-3/-1

r=+3

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