3(x+2)+1=(x-3)+12

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Solution for 3(x+2)+1=(x-3)+12 equation: 



3(x+2)+1=(x-3)+12

We move all terms to the left:

3(x+2)+1-((x-3)+12)=0

We multiply parentheses

3x-((x-3)+12)+6+1=0



We calculate terms in parentheses: -((x-3)+12), so:

(x-3)+12

We get rid of parentheses

x-3+12

We add all the numbers together, and all the variables

x+9

Back to the equation:

-(x+9)



We add all the numbers together, and all the variables

3x-(x+9)+7=0

We get rid of parentheses

3x-x-9+7=0

We add all the numbers together, and all the variables

2x-2=0

We move all terms containing x to the left, all other terms to the right

2x=2

x=2/2

x=1

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