5(r+3)=2(4-r)

Solution for 5(r+3)=2(4-r) equation:

5(r+3)=2(4-r)

We move all terms to the left:

5(r+3)-(2(4-r))=0

We add all the numbers together, and all the variables

5(r+3)-(2(-1r+4))=0

We multiply parentheses

5r-(2(-1r+4))+15=0


We calculate terms in parentheses: -(2(-1r+4)), so:

2(-1r+4)

We multiply parentheses

-2r+8

Back to the equation:

-(-2r+8)


We get rid of parentheses

5r+2r-8+15=0

We add all the numbers together, and all the variables

7r+7=0

We move all terms containing r to the left, all other terms to the right

7r=-7

r=-7/7

r=-1