5(r+2)=3(r-2)

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Solution for 5(r+2)=3(r-2) equation:



5(r+2)=3(r-2)
We move all terms to the left:
5(r+2)-(3(r-2))=0
We multiply parentheses
5r-(3(r-2))+10=0
We calculate terms in parentheses: -(3(r-2)), so:
3(r-2)
We multiply parentheses
3r-6
Back to the equation:
-(3r-6)
We get rid of parentheses
5r-3r+6+10=0
We add all the numbers together, and all the variables
2r+16=0
We move all terms containing r to the left, all other terms to the right
2r=-16
r=-16/2
r=-8

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