2(4-3x)+12=7x-5(2x*7)

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Solution for 2(4-3x)+12=7x-5(2x*7) equation: 



2(4-3x)+12=7x-5(2x*7)

We move all terms to the left:

2(4-3x)+12-(7x-5(2x*7))=0

We add all the numbers together, and all the variables

2(-3x+4)-(7x-5(+2x*7))+12=0

We multiply parentheses

-6x-(7x-5(+2x*7))+8+12=0



We calculate terms in parentheses: -(7x-5(+2x*7)), so:

7x-5(+2x*7)

We multiply parentheses

7x-70x

We add all the numbers together, and all the variables

-63x

Back to the equation:

-(-63x)



We add all the numbers together, and all the variables

-6x-(-63x)+20=0

We get rid of parentheses

-6x+63x+20=0

We add all the numbers together, and all the variables

57x+20=0

We move all terms containing x to the left, all other terms to the right

57x=-20

x=-20/57

x=-20/57

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