3x+2x(x+2)=20-(2x-5)

Solution for 3x+2x(x+2)=20-(2x-5) equation:

3x+2x(x+2)=20-(2x-5)

We move all terms to the left:

3x+2x(x+2)-(20-(2x-5))=0

We multiply parentheses

2x^2+3x+4x-(20-(2x-5))=0


We calculate terms in parentheses: -(20-(2x-5)), so:

20-(2x-5)

determiningTheFunctionDomain
-(2x-5)+20

We get rid of parentheses

-2x+5+20

We add all the numbers together, and all the variables

-2x+25

Back to the equation:

-(-2x+25)


We add all the numbers together, and all the variables

2x^2+7x-(-2x+25)=0

We get rid of parentheses

2x^2+7x+2x-25=0

We add all the numbers together, and all the variables

2x^2+9x-25=0

a = 2; b = 9; c = -25;
Δ = b2-4ac
Δ = 92-4·2·(-25)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{281}}{2*2}=\frac{-9-\sqrt{281}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{281}}{2*2}=\frac{-9+\sqrt{281}}{4}
$