12x+20x=4+22x

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Solution for 12x+20x=4+22x equation: 



12x+20x=4+22x

We move all terms to the left:

12x+20x-(4+22x)=0

We add all the numbers together, and all the variables

12x+20x-(22x+4)=0

We add all the numbers together, and all the variables

32x-(22x+4)=0

We get rid of parentheses

32x-22x-4=0

We add all the numbers together, and all the variables

10x-4=0

We move all terms containing x to the left, all other terms to the right

10x=4

x=4/10

x=2/5

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