5(p-1)+6/8=7-(3-2p)/12p=

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Solution for 5(p-1)+6/8=7-(3-2p)/12p= equation: 



5(p-1)+6/8=7-(3-2p)/12p=

We move all terms to the left:

5(p-1)+6/8-(7-(3-2p)/12p)=0



Domain of the equation: 12p)!=0

p!=0/1

p!=0

p∈R



We add all the numbers together, and all the variables

5(p-1)-(7-(-2p+3)/12p)+6/8=0

We multiply parentheses

5p-(7-(-2p+3)/12p)-5+6/8=0

We calculate fractions


5p+(-(7-(-2p+3)*8)/12p*8)+72p/12p*8)-5=0



We calculate terms in parentheses: +(-(7-(-2p+3)*8)/12p*8), so:

-(7-(-2p+3)*8)/12p*8

We multiply all the terms by the denominator


-(7-(-2p+3)*8)



We calculate terms in parentheses: -(7-(-2p+3)*8), so:

7-(-2p+3)*8

determiningTheFunctionDomain
-(-2p+3)*8+7

We multiply parentheses

16p-24+7

We add all the numbers together, and all the variables

16p-17

Back to the equation:

-(16p-17)



We get rid of parentheses

-16p+17

Back to the equation:

+(-16p+17)



We get rid of parentheses

5p-16p+72p/12p*8)-5+17=0

We multiply all the terms by the denominator


5p*12p*8)-5+17-16p*12p*8)-5+17+72p=0

Wy multiply elements

46080p^5*8=0

We do not support eppression: p^5

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