125/x=80/(1-x)+45

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Solution for 125/x=80/(1-x)+45 equation: 



125/x=80/(1-x)+45

We move all terms to the left:

125/x-(80/(1-x)+45)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: (1-x)+45)!=0

We move all terms containing x to the left, all other terms to the right

-x)+45!=-1

x!=-1/1

x!=-1

x∈R



We add all the numbers together, and all the variables

125/x-(80/(-1x+1)+45)=0

We calculate fractions


(-125x+125)/(-1x^2+x)+(-(80*x)/(-1x^2+x)=0



We calculate terms in parentheses: +(-(80*x)/(-1x^2+x), so:

-(80*x)/(-1x^2+x

We add all the numbers together, and all the variables

-(+80x)/(-1x^2+x

We multiply all the terms by the denominator


-(+80x)

We get rid of parentheses

-80x

Back to the equation:

+(-80x)



We get rid of parentheses

(-125x+125)/(-1x^2+x)-80x=0

We multiply all the terms by the denominator


-80x*(-1x^2+x)+(-125x+125)=0

We multiply parentheses

80x^3-80x^2+(-125x+125)=0

We get rid of parentheses

80x^3-80x^2-125x+125=0

We do not support expression: x^3

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