5(p+2)+(2p-1)=8(3p-4)

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Solution for 5(p+2)+(2p-1)=8(3p-4) equation: 



5(p+2)+(2p-1)=8(3p-4)

We move all terms to the left:

5(p+2)+(2p-1)-(8(3p-4))=0

We multiply parentheses

5p+(2p-1)-(8(3p-4))+10=0

We get rid of parentheses

5p+2p-(8(3p-4))-1+10=0



We calculate terms in parentheses: -(8(3p-4)), so:

8(3p-4)

We multiply parentheses

24p-32

Back to the equation:

-(24p-32)



We add all the numbers together, and all the variables

7p-(24p-32)+9=0

We get rid of parentheses

7p-24p+32+9=0

We add all the numbers together, and all the variables

-17p+41=0

We move all terms containing p to the left, all other terms to the right

-17p=-41

p=-41/-17

p=2+7/17

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