5(n-3)=4(n-2)

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Solution for 5(n-3)=4(n-2) equation: 



5(n-3)=4(n-2)

We move all terms to the left:

5(n-3)-(4(n-2))=0

We multiply parentheses

5n-(4(n-2))-15=0



We calculate terms in parentheses: -(4(n-2)), so:

4(n-2)

We multiply parentheses

4n-8

Back to the equation:

-(4n-8)



We get rid of parentheses

5n-4n+8-15=0

We add all the numbers together, and all the variables

n-7=0

We move all terms containing n to the left, all other terms to the right

n=7

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