5(n-3)-2=-33-(n+2)

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Solution for 5(n-3)-2=-33-(n+2) equation: 



5(n-3)-2=-33-(n+2)

We move all terms to the left:

5(n-3)-2-(-33-(n+2))=0

We multiply parentheses

5n-(-33-(n+2))-15-2=0



We calculate terms in parentheses: -(-33-(n+2)), so:

-33-(n+2)

determiningTheFunctionDomain
-(n+2)-33

We get rid of parentheses

-n-2-33

We add all the numbers together, and all the variables

-1n-35

Back to the equation:

-(-1n-35)



We add all the numbers together, and all the variables

5n-(-1n-35)-17=0

We get rid of parentheses

5n+1n+35-17=0

We add all the numbers together, and all the variables

6n+18=0

We move all terms containing n to the left, all other terms to the right

6n=-18

n=-18/6

n=-3

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