(7x-3)+(3x+11)=80

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Solution for (7x-3)+(3x+11)=80 equation: 



(7x-3)+(3x+11)=80

We move all terms to the left:

(7x-3)+(3x+11)-(80)=0

We get rid of parentheses

7x+3x-3+11-80=0

We add all the numbers together, and all the variables

10x-72=0

We move all terms containing x to the left, all other terms to the right

10x=72

x=72/10

x=7+1/5

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