5(m+2)-3(m-5)=29

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Solution for 5(m+2)-3(m-5)=29 equation: 



5(m+2)-3(m-5)=29

We move all terms to the left:

5(m+2)-3(m-5)-(29)=0

We multiply parentheses

5m-3m+10+15-29=0

We add all the numbers together, and all the variables

2m-4=0

We move all terms containing m to the left, all other terms to the right

2m=4

m=4/2

m=2

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