3/4(4a-5)-5/12(3a-4)=1/6

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Solution for 3/4(4a-5)-5/12(3a-4)=1/6 equation: 



3/4(4a-5)-5/12(3a-4)=1/6

We move all terms to the left:

3/4(4a-5)-5/12(3a-4)-(1/6)=0



Domain of the equation: 4(4a-5)!=0

a∈R





Domain of the equation: 12(3a-4)!=0

a∈R



We add all the numbers together, and all the variables

3/4(4a-5)-5/12(3a-4)-(+1/6)=0

We get rid of parentheses

3/4(4a-5)-5/12(3a-4)-1/6=0

We calculate fractions


(216a3/(4(4a-5)*12(3a-4)*6)+(-120a4/(4(4a-5)*12(3a-4)*6)+(-48a^24/(4(4a-5)*12(3a-4)*6)=0



We calculate terms in parentheses: +(216a3/(4(4a-5)*12(3a-4)*6)+(-120a4/(4(4a-5)*12(3a-4)*6)+(-48a^24/(4(4a-5)*12(3a-4)*6), so:

216a3/(4(4a-5)*12(3a-4)*6)+(-120a4/(4(4a-5)*12(3a-4)*6)+(-48a^24/(4(4a-5)*12(3a-4)*6

We do not support eapression: a^24

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