5(m+1)+6=3(4+m)-12m-1

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Solution for 5(m+1)+6=3(4+m)-12m-1 equation: 



5(m+1)+6=3(4+m)-12m-1

We move all terms to the left:

5(m+1)+6-(3(4+m)-12m-1)=0

We add all the numbers together, and all the variables

5(m+1)-(3(m+4)-12m-1)+6=0

We multiply parentheses

5m-(3(m+4)-12m-1)+5+6=0



We calculate terms in parentheses: -(3(m+4)-12m-1), so:

3(m+4)-12m-1

We add all the numbers together, and all the variables

-12m+3(m+4)-1

We multiply parentheses

-12m+3m+12-1

We add all the numbers together, and all the variables

-9m+11

Back to the equation:

-(-9m+11)



We add all the numbers together, and all the variables

5m-(-9m+11)+11=0

We get rid of parentheses

5m+9m-11+11=0

We add all the numbers together, and all the variables

14m=0

m=0/14

m=0

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