If it's not what You are looking for type in the equation solver your own equation and let us solve it.
k/4=4k*
We move all terms to the left:
k/4-(4k*)=0
We add all the numbers together, and all the variables
k/4-(+4k*)=0
We get rid of parentheses
k/4-4k*=0
We multiply all the terms by the denominator
k-(4k*)*4=0
We add all the numbers together, and all the variables
k-(+4k*)*4=0
We multiply parentheses
-16k^2+k=0
a = -16; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-16)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-16}=\frac{-2}{-32} =1/16 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-16}=\frac{0}{-32} =0 $
| 1.9=5d+0.9 | | (8x+67)/3=0 | | -35=a20 | | 35a=-20 | | 17x-15=180 | | 125+20+t=180 | | x+x+15+2x=3x | | /7(12x+34)=−5+58x | | -6(z+1)=24 | | 2(x+7)=5(x-7) | | 7(1/2x+3/4)=5+5/8x | | 9x-12=56 | | 6x-7+5x+1=10 | | u/36=4u* | | 11-3x=44+2x | | 2(-4y+-3)=-14 | | 0,8x+0.6x=42 | | 7x+4=9x-24 | | 13.1=(x)x150 | | (9x+16)=(5x-14) | | c(2)=c(2-1)+10 | | 2y-4=5y-12 | | 42+5t=67 | | 1.25x+2=17 | | (8x+2)=(11x-25) | | K+9=6(k-11) | | x+9+6x-5+(180+9x-24)=180 | | 45.5=7h, | | 3x2+2x+11=0 | | -6k+36=6k | | (11x-25)+(4x+1)=180 | | -16=-5+4r |