5(k-3)-5k=10+2(3k+1)

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Solution for 5(k-3)-5k=10+2(3k+1) equation: 



5(k-3)-5k=10+2(3k+1)

We move all terms to the left:

5(k-3)-5k-(10+2(3k+1))=0

We add all the numbers together, and all the variables

-5k+5(k-3)-(10+2(3k+1))=0

We multiply parentheses

-5k+5k-(10+2(3k+1))-15=0



We calculate terms in parentheses: -(10+2(3k+1)), so:

10+2(3k+1)

determiningTheFunctionDomain
2(3k+1)+10

We multiply parentheses

6k+2+10

We add all the numbers together, and all the variables

6k+12

Back to the equation:

-(6k+12)



We add all the numbers together, and all the variables

-(6k+12)-15=0

We get rid of parentheses

-6k-12-15=0

We add all the numbers together, and all the variables

-6k-27=0

We move all terms containing k to the left, all other terms to the right

-6k=27

k=27/-6

k=-4+1/2

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