60=4(k+)+2(k-3)

Solution for 60=4(k+)+2(k-3) equation:

60=4(k+)+2(k-3)

We move all terms to the left:

60-(4(k+)+2(k-3))=0

We add all the numbers together, and all the variables

-(4(+k)+2(k-3))+60=0


We calculate terms in parentheses: -(4(+k)+2(k-3)), so:

4(+k)+2(k-3)

We multiply parentheses

4k+2k-6

We add all the numbers together, and all the variables

6k-6

Back to the equation:

-(6k-6)


We get rid of parentheses

-6k+6+60=0

We add all the numbers together, and all the variables

-6k+66=0

We move all terms containing k to the left, all other terms to the right

-6k=-66

k=-66/-6

k=+11