5(k+2)-7/6=13-(-4-k)

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Solution for 5(k+2)-7/6=13-(-4-k) equation: 



5(k+2)-7/6=13-(-4-k)

We move all terms to the left:

5(k+2)-7/6-(13-(-4-k))=0

We add all the numbers together, and all the variables

5(k+2)-(13-(-1k-4))-7/6=0

We multiply parentheses

5k-(13-(-1k-4))+10-7/6=0

We multiply all the terms by the denominator


5k*6-((13-(-1k-4)))*6-7+10*6=0

We add all the numbers together, and all the variables

5k*6-((13-(-1k-4)))*6+53=0

Wy multiply elements

30k-((13-(-1k-4)))*6+53=0

We move all terms containing k to the left, all other terms to the right

30k-((13-(-1k-4)))*6=-53

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