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(12x-15)=2(2x-3)+1
We move all terms to the left:
(12x-15)-(2(2x-3)+1)=0
We get rid of parentheses
12x-(2(2x-3)+1)-15=0
We calculate terms in parentheses: -(2(2x-3)+1), so:We get rid of parentheses
2(2x-3)+1
We multiply parentheses
4x-6+1
We add all the numbers together, and all the variables
4x-5
Back to the equation:
-(4x-5)
12x-4x+5-15=0
We add all the numbers together, and all the variables
8x-10=0
We move all terms containing x to the left, all other terms to the right
8x=10
x=10/8
x=1+1/4
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