5(h+3)=2(4h-10)+14

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Solution for 5(h+3)=2(4h-10)+14 equation: 



5(h+3)=2(4h-10)+14

We move all terms to the left:

5(h+3)-(2(4h-10)+14)=0

We multiply parentheses

5h-(2(4h-10)+14)+15=0



We calculate terms in parentheses: -(2(4h-10)+14), so:

2(4h-10)+14

We multiply parentheses

8h-20+14

We add all the numbers together, and all the variables

8h-6

Back to the equation:

-(8h-6)



We get rid of parentheses

5h-8h+6+15=0

We add all the numbers together, and all the variables

-3h+21=0

We move all terms containing h to the left, all other terms to the right

-3h=-21

h=-21/-3

h=+7

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