5(d-4)=7(2d+1)

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Solution for 5(d-4)=7(2d+1) equation: 



5(d-4)=7(2d+1)

We move all terms to the left:

5(d-4)-(7(2d+1))=0

We multiply parentheses

5d-(7(2d+1))-20=0



We calculate terms in parentheses: -(7(2d+1)), so:

7(2d+1)

We multiply parentheses

14d+7

Back to the equation:

-(14d+7)



We get rid of parentheses

5d-14d-7-20=0

We add all the numbers together, and all the variables

-9d-27=0

We move all terms containing d to the left, all other terms to the right

-9d=27

d=27/-9

d=-3

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