8(v+4)-2v=4(4v+3)-20

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Solution for 8(v+4)-2v=4(4v+3)-20 equation: 



8(v+4)-2v=4(4v+3)-20

We move all terms to the left:

8(v+4)-2v-(4(4v+3)-20)=0

We add all the numbers together, and all the variables

-2v+8(v+4)-(4(4v+3)-20)=0

We multiply parentheses

-2v+8v-(4(4v+3)-20)+32=0



We calculate terms in parentheses: -(4(4v+3)-20), so:

4(4v+3)-20

We multiply parentheses

16v+12-20

We add all the numbers together, and all the variables

16v-8

Back to the equation:

-(16v-8)



We add all the numbers together, and all the variables

6v-(16v-8)+32=0

We get rid of parentheses

6v-16v+8+32=0

We add all the numbers together, and all the variables

-10v+40=0

We move all terms containing v to the left, all other terms to the right

-10v=-40

v=-40/-10

v=+4

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